1 / 4. Find step-by-step Calculus solutions and your answer to the following textbook question: At noon, ship A is 90 km west of ship B. Ship A is sailing south at 20 km/h and ship B is sailing north at 10 km/h. How fast is the distance between the ships changing at 4:00 PM?.
In Scientific Notation. 55 kilometers per hour. = 5.5 x 10 1 kilometers per hour. ≈ 3.41754 x 10 1 miles per hour.
At noon, ship a is 50 km west of ship b. ship a is sailing south at 10 km/h and ship b is sailing north at 20 km/h. how fast is the distance between the ships changing at 4:00 pm? (round your answer to one decimal place.) 23.05 incorrect: your answer is incorrect. km/h
50-59: 4.43 km/h: 2.75 mph >60: 4.34 km/h: 2.7 mph >65: 3.42 km/h: 2.1 mph: a 2018 study sought to generalize what it means to answer the question of how fast is fast enough. They found that
In Scientific Notation. 45 kilometers per hour. = 4.5 x 10 1 kilometers per hour. ≈ 2.79617 x 10 1 miles per hour.
In Scientific Notation. 60 kilometers per hour. = 6 x 10 1 kilometers per hour. ≈ 3.72823 x 10 1 miles per hour.
. 261 222 387 479 113 314 472 2
is 50 km h fast
